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Anti-Human EIF5A2 Polyclonal Antibody (HP218014)

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概要
カタログ番号HP218014
説明
Anti-Human EIF5A2 Polyclonal Antibody (HP218014) is a rabbit polyclonal antibody detecting EIF5A2 in ELISA, IHC, WB. Suitable for Human, Mouse.
Highlights
  • ●Affinity Purified — Minimal background and high purity for reliable results.
  • ●Multi-Application — Validated across multiple applications.
  • ●Multi-Species — Cross-reactive for translational research.
種反応性Human, Mouse
アプリケーションELISA, IHC, WB
宿主種Rabbit
クローン性Polyclonal
アイソタイプIgG
免疫原 E. coli - derived recombinant Human EIF5A2 (Ser16-Lys153).
ターゲット eIF-5A2, eIF-5A-2, Eukaryotic translation initiation factor 5A-2, EIF5A2, Eukaryotic initiation factor 5A isoform 2
精製 Purified by antigen affinity column.
アクセッション番号 Q9GZV4
形態 Liquid
保存バッファー 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

データシートのハードコピーまたはロット固有のCOAに記載された具体的なバッファー情報を参照してください。

製品使用情報
アプリケーション 希釈
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
安定性と保存 Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Eukaryotic translation initiation factor 5A-2 (EIF5A2) is a ~16 kDa protein. Translation factor that promotes translation elongation and termination, particularly upon ribosome stalling at specific amino acid sequence contexts. Binds between the exit (E) and peptidyl (P) site of the ribosome and promotes rescue of stalled ribosome: specifically required for efficient translation of polyproline-containing peptides as well as other motifs that stall the ribosome. Acts as a ribosome quality control (RQC) cofactor by joining the RQC complex to facilitate peptidyl transfer during CAT tailing step. Also involved in actin dynamics and cell cycle progression, mRNA decay and probably in a pathway involved in stress response and maintenance of cell wall integrity.

1. Clement, PM. et al. (2003) European journal of biochemistry 270, 4254-63. PMID: 14622290
注意事項 For research use only.
イメージ
参考文献
Formula
Mass (g) = Concentration (mol/L) × Volume (L) × MW (g/mol)
Enter any 2 of Mass, Concentration, Volume + Molecular Weight to solve for the unknown.
Mass
=
Concentration
×
Volume
Molecular Weight *
g/mol
Formula
C₁ × V₁ = C₂ × V₂
Enter any 3 of the 4 values to solve for the unknown.
Stock Solution
C₁ (Stock Conc.)
×
V₁ (Stock Vol.)
=
Working Solution
C₂ (Working Conc.)
×
V₂ (Working Vol.)
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