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Anti-Human GTF2H5 Polyclonal Antibody (HD338014)

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Vista general
Número de catálogoHD338014
Descripción
Anti-Human GTF2H5 Polyclonal Antibody (HD338014) is a rabbit polyclonal antibody detecting GTF2H5. Suitable for Human and Mouse.
Highlights
  • ●Multi-Species — Cross-reactive for translational research.
Reactividad de especiesHuman, Mouse
AplicacionesELISA, IHC, WB
Especie huéspedRabbit
ClonalidadPolyclonal
IsotipoIgG
Inmunógeno E. coli - derived recombinant Human GTF2H5 (Val2-Lys71).
Objetivo C6orf175, GTF2H5, General transcription factor IIH polypeptide 5, General transcription factor IIH subunit 5, TFB5 ortholog, TFIIH basal transcription factor complex TTD-A subunit, TFIIH subunit p8, TTDA
Nivel de endotoxinas Please contact with the lab for this information.
Purificación Purified by antigen affinity column.
Número de acceso Q6ZYL4
Forma Liquid
Buffer de almacenamiento 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Consulte la información específica del buffer en la copia impresa del datasheet o en el COA específico del lote.

Información de uso del producto
Aplicación Dilución
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
Fondo

General transcription factor IIH subunit 5 (GTF2H5) is a ~8 kDa protein. Component of the general transcription and DNA repair factor IIH (TFIIH) core complex, which is involved in general and transcription-coupled nucleotide excision repair (NER) of damaged DNA and, when complexed to CAK, in RNA transcription by RNA polymerase II. In NER, TFIIH acts by opening DNA around the lesion to allow the excision of the damaged oligonucleotide and its replacement by a new DNA fragment. In transcription, TFIIH has an essential role in transcription initiation. When the pre-initiation complex (PIC) has been established, TFIIH is required for promoter opening and promoter escape. Phosphorylation of the C-terminal tail (CTD) of the largest subunit of RNA polymerase II by the kinase module CAK controls the initiation of transcription.

Nota For research use only
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Formula
Mass (g) = Concentration (mol/L) × Volume (L) × MW (g/mol)
Enter any 2 of Mass, Concentration, Volume + Molecular Weight to solve for the unknown.
Mass
=
Concentration
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Volume
Molecular Weight *
g/mol
Formula
C₁ × V₁ = C₂ × V₂
Enter any 3 of the 4 values to solve for the unknown.
Stock Solution
C₁ (Stock Conc.)
×
V₁ (Stock Vol.)
=
Working Solution
C₂ (Working Conc.)
×
V₂ (Working Vol.)
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