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Обзор
Каталожный номерJN882052
Описание
Recombinant E.coli Tn5 Protein, N-His (JN882052) expressed in E. coli. Purity: >90% as determined by SDS-PAGE..
Highlights
  • ●E. coli Expression — High-yield, cost-effective production.
  • ●High Purity — >90% as determined by SDS-PAGE.
Система экспрессииE. coli
Номер доступаQ46731
Длина белкаMet1-Ile476
ПримененияELISA, Immunogen, SDS-PAGE, WB, Bioactivity testing in progress
ВидыEscherichia coli
Характер Recombinant
Уровень эндотоксинов Please contact with the lab for this information.
Чистота >90% as determined by SDS-PAGE.
Прогнозируемая молекулярная масса 55.84 kDa
Форма Lyophilized
Буфер хранения Lyophilized from a solution in PBS pH 7.4, 1 mM EDTA, 4% Trehalose, 1% Mannitol.

Пожалуйста, обратитесь к конкретной информации о буфере в печатной версии даташита или в индивидуальном сертификате качества (COA) для партии.

Реконституция Reconstitute in sterile water for a stock solution. A copy of datasheet will be provided with the products, please refer to it for details.
Доставка In general, proteins are provided as lyophilized powder/frozen liquid. They are shipped out with dry ice/blue ice unless customers require otherwise.
Устойчивость и хранение Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
Альтернативные названияTransposase for transposon Tn5, EC:3.1.-.-, Tnp, tnpA, tnp
Фон

Transposase for transposon Tn5 is a ~53 kDa protein. Mediates transposition of transposon Tn5 by a 'cut and paste' mechanism. First, the monomeric transposase binds the 19 bp inverted DNA repeats flanking the transposon. Then, dimerization of the DNA-bound transposase creates a synaptic DNA complex. After nicking of the first DNA strand, excision of the transposon proceeds through a series of intermediates. The transposase then mediates the insertion of the transposon at a new site by strand transfer.

Примечание For research use only
Изображения
Ссылки
Formula
Mass (g) = Concentration (mol/L) × Volume (L) × MW (g/mol)
Enter any 2 of Mass, Concentration, Volume + Molecular Weight to solve for the unknown.
Mass
=
Concentration
×
Volume
Molecular Weight *
g/mol
Formula
C₁ × V₁ = C₂ × V₂
Enter any 3 of the 4 values to solve for the unknown.
Stock Solution
C₁ (Stock Conc.)
×
V₁ (Stock Vol.)
=
Working Solution
C₂ (Working Conc.)
×
V₂ (Working Vol.)
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