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Anti-Mycobacterium tuberculosis Isocitrate lyase/ICL Polyclonal Antibody (JN930024)

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Overview
Catalog No.JN930024
Description
Anti-Mycobacterium tuberculosis Isocitrate lyase/ICL Polyclonal Antibody (JN930024) is a rabbit polyclonal antibody detecting Isocitrate lyase. Suitable for Mycobacterium tuberculosis and Mycobacterium bovis.
Highlights
  • Multi-Species — Cross-reactive for translational research.
Species reactivityMycobacterium tuberculosis, Mycobacterium bovis
ApplicationsELISA, IHC, WB
Host speciesRabbit
IsotypeIgG
Clonality Polyclonal
Immunogen E. coli - derived recombinant Mycobacterium tuberculosis Isocitrate lyase/ICL (Met1-His428).
Target EC:4.1.3.1, ICL, Isocitrase, Isocitratase, Isocitrate lyase, icl
Endotoxin level Please contact with the lab for this information.
Purification Purified by antigen affinity column.
Accession P9WKK7
Form Liquid
Storage buffer 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

Product Usage Information
Application Dilution
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
Background

Isocitrate lyase (ICL) is a ~47 kDa protein. Involved in the persistence and virulence of M.tuberculosis. Catalyzes the reversible formation of succinate and glyoxylate from isocitrate, a key step of the glyoxylate cycle, which operates as an anaplerotic route for replenishing the tricarboxylic acid cycle during growth on fatty acid substrates. It could also catalyze the formation of pyruvate and succinate from 2-methylisocitrate, a key step in the methylcitrate cycle (propionate degradation route).

1. Sharma, V. et al. (2000) Nature structural biology 7, 663-8. PMID: 10932251
2. McKinney, JD. et al. (2000) Nature 406, 735-8. PMID: 10963599
3. Kumar, R. et al. (2008) Proteins 72, 892-900. PMID: 18275086
4. Moynihan, MM. et al. (2014) Biochemistry 53, 178-87. PMID: 24354272
Note For research use only
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Formula
Mass (g) = Concentration (mol/L) × Volume (L) × MW (g/mol)
Enter any 2 of Mass, Concentration, Volume + Molecular Weight to solve for the unknown.
Mass
=
Concentration
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Volume
Molecular Weight *
g/mol
Formula
C₁ × V₁ = C₂ × V₂
Enter any 3 of the 4 values to solve for the unknown.
Stock Solution
C₁ (Stock Conc.)
×
V₁ (Stock Vol.)
=
Working Solution
C₂ (Working Conc.)
×
V₂ (Working Vol.)
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